Physics Question?

Question

An elevator starts from rest with a constant upward acceleration and moves 1 m in the first 1.5 s. A passenger in the elevator is holding a 9.2 kg bundle at the end of a vertical cord. The acceleration of gravity is 9.8 m/s^2. What is the tension in the cord as the elevator accelerates? Answer in units of N.

Answer 1

accelleration = rate / time

so, the accelleration of the elevator is 2/3 m/s²

Add the forces together, and you have 9.8 + 2/3 =

98/10 + 2/3 = (294 + 20)/30 = 314/30 m/s²

f = m*a

f = 9.2kg * 314/30 m/s²
f = 288.88/3 N ~ 96.29333333.... N