For a right triangle with legs a and b and hypoteneuse c, a^2+b^2=c^2.
2006-10-30 10:46:15
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answer #1
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answered by Blue Jean 6
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so i'm assuming this is the problem: SQ=square root ^2=squared [10(SQ)2]^2= n^2+10^2 << [10SQ2]^2 becomes (100*4) which is 200 .... and 10^2 is 100 so thus: 200 = n^2+100 <
2016-05-22 13:08:55
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answer #2
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answered by ? 4
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a^2 + b^2 = c^2
where c is the hypotenuse of a right triangle and a and b are the other 2 sides.
2006-10-30 10:45:44
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answer #3
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answered by Anonymous
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a squared plus b squared equals c squared.
c is the hypotenuse of a right triangls, a and b are the other two legs.
2006-10-30 10:47:07
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answer #4
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answered by mom 7
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let h=hypotenuse of a rt triangle
let a & b= the other 2 sides
h^2=a^2+b^2
2006-10-30 11:08:40
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answer #5
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answered by yupchagee 7
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A squared plus B squared = C squared
2006-10-30 10:45:50
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answer #6
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answered by Professor Sheed 6
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a^2+b^2=c^2
a is one leg of right triangle
b is another
c is the hypotenuse
2006-10-30 10:50:40
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answer #7
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answered by futureastronaut1 3
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a^2 + b2 = c^2
where a & b = length of both sides of the right-angle triangle
c = hypotenus
2006-10-30 10:48:54
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answer #8
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answered by Anonymous
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a squared + b squared = c squared (put 2 as the squared symbol)
2006-10-30 10:47:27
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answer #9
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answered by Solomon 2
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a^2+b^2=c^2
a and b are the shorter sides.
c is the long side.
2006-10-30 10:49:09
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answer #10
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answered by Uchiha Sasuke 2
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