what is a single trig idnetitiy answer to (sin x)(tan x)?

Answer 1

okay

(sinx)(sinx/cosx)

(sinx)(sinx)(1/cosx)
(sinx^2)(secx)

this makes no sense because you have to have it set equal to something...like cosx^2+sinx^2=1 or something

Answer 2

= (sin x)*(sin x / cos x)
= sin^2 (x) / cos x
= [(1 - cos2x)sec x] / 2

Note that 1/cos x = sec x

And cos2x is derived from here:
cos2x = 1 - 2sin^2 (x)
2sin^2(x) = 1 - cos 2x
sin^2(x) = (1 - cos 2x)/2

There are many ways to solve it actually, it's up to your own creativity to obtain a solution for it.

Answer 3

tanx = sin x/cos x
(sin x)(tan x) = (sin x)(sinx/cosx) = (sinx)^2 / cosx
(sinx)^2 + (cosx)^2 = 1 so (sinx)^2 = 1 - (cosx)^2
(sinx)(tanx) = (1 -(cosx)^2)/cosx

Answer 4

(sinx)(tanx) = (sinx)(sinx/cosx) = (sinx^2)/(cosx) = (1 - cos(x)^2)/(cos(x)) = (1/(cos(x))) - cos(x) = sec(x) - cos(x)

only if your problem was (sin(x))(cot(x)) = (sin(x))(cos(x)/sin(x)) = cos(x)