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Using the letters A, B, and C, how many differnent three letter codes can u find?

please help
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xPPPPPPPPPPPPPPP

2006-10-30 09:45:30 · 4 answers · asked by (: 2 in Science & Mathematics Mathematics

4 answers

If each letter can be used more than once there are 27: each position can be any of 3 letters, so it is 3*3*3.

If each letter is used once there are 6. The first position can be any of 3, the second any of the remaining2, the third the last one, so it is 3*2*1.

2006-10-30 09:48:41 · answer #1 · answered by sofarsogood 5 · 1 0

We have A, B and C letters.

1) If we can repeat the letters we obtain:

3 X 3 X 3 = 27 different three letter codes.


2) If we can't repeat the letters we have:

3 X 2 X 1 = 6 different three letter codes.

2006-11-07 16:51:29 · answer #2 · answered by frank 7 · 0 0

Three factorial: 3!, one for each letter to be scrambled at random:
3! = 3 x 2 x 1 = 6.

2006-10-30 17:50:26 · answer #3 · answered by Action 4 · 0 0

I assume you can't have AAA, BBB, CCC, AAB, etc, but only the three.


the answer is 6

ABC ACB BAC BCA CAB CBA

2006-10-30 17:58:07 · answer #4 · answered by mom 7 · 0 0

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