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does
1-x(1+x^2)^-1/2 = -1 / x(1+x^2)^1/2 ??

2006-10-30 09:28:23 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

No, not in general.
1 - x(1+x^2)^(-1/2)
= 1 - x/sqrt(1+x^2)
= (sqrt(1+x^2) - x)/sqrt(1+x^2)

2006-10-30 09:31:59 · answer #1 · answered by MsMath 7 · 0 1

Not the way you've got it written. You have only the quantity
(1+x)^-1/2 power so that becomes (1+x)^1/2 in the denominator of both sides of the equation. that leaves you with 1-x on the left, but 1/x on the right (which could be written as 1/x(1+x)^1/2

2006-10-30 18:06:11 · answer #2 · answered by mom 7 · 0 0

if you mean 1-[x*(1+x^2)^-1/2] then it's a no
if you mean (1-x)*[(1+x^2)^-1/2], it's also a no.

I can't see how you got that answer.
The x variable can't jump from the numerator to denominator just like that.

Your answer should be
(1-x)*[(1+x^2)^-1/2] = (1-x) / [(1+x^2)^1/2]
or 1-[x*(1+x^2)^-1/2] = 1- (x / [(1+x^2)^1/2])

whichever's applicable.

The negative power denotes the inverse of the value that you are referring to. (eg: x^-2 = 1/(x^2) )

Do remember to include brackets for further clarity of your question.

2006-10-30 17:45:24 · answer #3 · answered by forty*winks 1 · 0 1

if you are doing distributive property it equals 1-x+x^2 to the -1/2 power

2006-10-30 17:39:07 · answer #4 · answered by Anonymous · 0 1

not at all

s

2006-11-03 13:05:20 · answer #5 · answered by locuaz 7 · 0 0

yes

2006-10-30 17:30:24 · answer #6 · answered by Little miss naughty 2 · 0 1

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