How much juice will the pitcher hold?
What is the surface area of the pitcher?
2006-10-30 09:22:49 · 6 answers · asked by Ramon P 2 in Science & Mathematics ➔ Mathematics
Volume = area of base times height
Area of base = area of circle = pi (radius)^2 = pi(6)^2 = 36pi
height = 30
V = (36pi)(30) = 1080pi = 3392.92 cm cubed
Surface area = 2(area of base) + (circumference of circle)(height)
area of base = 36pi
circumference of circle = 2pi(r) = 2pi(6) = 12 pi
height = 30
SA = 2(36pi) + (12pi)(30) = 72pi + 360pi
SA = 432pi = 1357.17 cm squared
2006-10-30 09:25:00 · answer #1 · answered by MsMath 7 · 0⤊ 1⤋
V=pi r^2 h=pi 6^2 30=3393cm^3
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2006-11-03 13:08:30 · answer #2 · answered by locuaz 7 · 0⤊ 0⤋
You want the volume. Find the area of the base (circle) and multiply it by the height.
3.14x6x6x30=3391.2 cubic cm
for the surface area, you want to add the area of teh base (times two if there is a cover, and add the lateral surface area which is found by myltiplying 3.14 x diameter (the circumference of the base) times the height of the cylinder.
2x3.14x36 + 3.14x12x30
226.08+1130.4=1353.48square cm
2006-10-30 18:27:29 · answer #3 · answered by mom 7 · 0⤊ 1⤋
V=pi*r^2*h=pi*6^2*30=3393cm^3 or 3.393l
2006-10-30 17:33:57 · answer #4 · answered by yupchagee 7 · 0⤊ 1⤋
V = pi * r^2 * h
V = pi * 6^2 * 30cm
V = 36pi * 30
V = 1080pi or about 3392.92 cm^3
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T = 2 * Pi * r(r + h)
T = 2pi * 6(6 + 30)
T = 2pi * 6(36)
T = 2pi * 216
T = 432pi or about 1357.168cm^2
2006-10-30 19:34:16 · answer #5 · answered by Sherman81 6 · 0⤊ 1⤋
v=1080picm^3
s.a.=432pi^2
2006-10-30 17:30:29 · answer #6 · answered by dreamer1202 1 · 0⤊ 1⤋