y=y^2 -40y+87 in the form y=a(x-h)^2 +k
2006-10-30 09:10:21 · 3 answers · asked by Aleister 2 in Science & Mathematics ➔ Mathematics
I'm assuming you have a typo.
y = x^2 - 40x + 87
Divide the coefficient of x by 2
-40/2 = -20
Square it
(-20)^2 = 400
Add and subtract 400
(x^2 - 40x + 400) + 87 - 400
y = (x-20)^2 - 313
2006-10-30 09:18:00 · answer #1 · answered by MsMath 7 · 0⤊ 1⤋
assuming you mean:
y = x^2 - 40x + 87
y= (x^2 - 40x + 400) + 87 - 400
y = (x-20)^2 - 313
so a=1, h= 20 and k=-313
s
2006-11-01 08:13:11 · answer #2 · answered by locuaz 7 · 0⤊ 0⤋
y = y^2 - 40y + 87
assuming you mean something like y = x^2 - 40x + 87
y = x^2 - 40x + 87
y = (x^2 - 40x) + 87
y = (x^2 - 40x + 400 - 400) + 87
y = ((x^2 - 40x + 400) - 400) + 87
y = (x^2 - 40x + 400) - 400 + 87
y = (x^2 - 40x + 400) - 313
y = (x - 20)^2 - 313
so
a = 1
h = 20
k = -313
2006-10-30 11:40:49 · answer #3 · answered by Sherman81 6 · 0⤊ 1⤋