WORLD RECORD: Alfred Wolfram set a record when he kissed 8,001 people in 8 hours at the Minnesota Renaissance Festival. To the nearest thenth, how many seconds did he average for each kiss? (1 hour(s) = 3600 seconds)
2006-10-30 08:46:49 · 8 answers · asked by RJ 2 in Science & Mathematics ➔ Mathematics
1 hour = 3600 seconds so 8 hours = 8*3600 = 28800 seconds
28800/8001 = 3.599
3.6 seconds per person
2006-10-30 08:50:49 · answer #1 · answered by MsMath 7 · 0⤊ 0⤋
I really think you should do this math yourself but the formula would to multiply the amount of hours by the amount of seconds per hour then take that answer and divide it by the amount of people and you will get the second per person
if this is homework you should stop putting this online you need to do these problems yourself or youll never learn anything
2006-10-30 16:59:06 · answer #2 · answered by amberslilsis06 2 · 0⤊ 1⤋
8 hours/8001people
= 28800seconds / 8001people
= 3.6 seconds/person
2006-10-30 16:51:11 · answer #3 · answered by Leah H 2 · 0⤊ 0⤋
with a break of 2 sec per person the time reduces to 1.6 sec per pesron
2006-11-02 09:26:24 · answer #4 · answered by Paritosh Vasava 3 · 0⤊ 1⤋
8 h * 3600 s/h / (8001 persons) = 3.6 s/person
2006-10-30 17:10:39 · answer #5 · answered by Dr. J. 6 · 0⤊ 0⤋
8hrs*3600sec/hr=28,800 sec
28800sec/8001people=3.6 sec/person.
Any idea WHY anybody would do this?
2006-10-30 16:49:50 · answer #6 · answered by yupchagee 7 · 1⤊ 0⤋
This is too easy. Figure it out yourself.
2006-10-30 16:48:38 · answer #7 · answered by Anonymous · 0⤊ 1⤋
3.6 sec
2006-10-30 16:49:58 · answer #8 · answered by ? 3 · 0⤊ 1⤋