The total cost of Sam’s lunch was $5.40. The cost of the drink was one-third the cost of the sandwich and the cost of the French Fries was twice as much as the drink. Find the price of each.
Help me please.
2006-10-30 08:44:21 · 6 answers · asked by jonwmcgown 2 in Education & Reference ➔ Homework Help
let the cost of the sandwich be $x.Therefore,the cost of the drink is x/3 and the cost of the French fries is 2x/3.Hence according to the problem: x+x/3+2x/3=5.40 => 3x+x+2x=5.40*3 [multiplying all the terms by3] =>6x=16,20 =>x=16.20/6=2.70 .Therefore the cost of sanwich was $2.70,the cost of drink was ($2.70/3 or)$0.90 and the cost of the French Fries was( $0.90*2 or)$1.80.
2006-10-30 09:22:27 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Hint: Start with the cost of the drink. If the drink costs x, then the sandwich is 3 times x, and the fries are 2 times x.
So x + 2x + 3x = $5.40.
2006-10-30 16:48:42 · answer #2 · answered by Carol S 2 · 0⤊ 0⤋
let x = the cost of the drink
so the sandwich cost 3x, and the fries cost 2x
Altogether you have x + 3x + 2x = $5.40
So, 6x = 5.40, which means x = 0.90
So the drink cost $0.90
The fries cost 2x, or $1.80
The sandwich cost 3x, or $2.70
Add them all up to check to make sure we did it right:
0.90 + 1.80 + 2.70 = 5.40 <<< checks out!
.
2006-10-30 16:47:41 · answer #3 · answered by djc 3 · 3⤊ 0⤋
Drink = $.90
Sandwich = $2.70
Fries = $1.80
Good luck
2006-10-30 16:56:44 · answer #4 · answered by God's Creation 2 · 0⤊ 0⤋
drink = $.90
sandwich = $2.70
fries = $1.80
2006-10-30 16:59:56 · answer #5 · answered by Super Girl 2 · 0⤊ 0⤋
drink = $.90
sandwich = $2.70
fries = $1.80
2006-10-30 16:51:19 · answer #6 · answered by Sir James the Dark 4 · 0⤊ 0⤋