can sumone solve this for me plz??

Question

15x^5 - 20x^4 = 6x^3 - 8x^2

Answer 1

15x^5 - 20x^4 - 6x^3 + 8x^2 = 0
x^2 (15x^3 - 20x^2 - 6x + 8) = 0

By trial and error and the Rational Roots Theorem, one solution to the system is x = 4/3

Dividing the polynomial by (x - 4/3) we get 15x^5 - 20x^4 - 6x^3 + 8x^2 = (x - 4/3)(15x^2 - 6)

Now we solve the 15x^2 - 6 part. We have to use the quadratic formula.

x = (-b±√[b² - 4ac]) / 2a

x = (-0±√[0² - 4(15)(-6)]) / 2(15)
x = ±√360 / 30
x = ±18.97 / 30
x = ±0.63

Therefore, x = 4/3, 0.63, -0.63

Answer 2

15x^5-20x^4 -6x^3 + 8x^2 = 0.
Removing the common factor of x^2
gives x = 0.
We are left with
15x^3-20x^2 -6x + 8 = 0.
Write it as
5x^2(3x-4) -2(3x-4) = 0.
Remove the common factor to get
(3x-4)(5x^2 -2) = 0.
I'll let you carry on from here and finish the job!

Answer 3

if the up arrow is a multiplies sign, then:

15x^5 - 20x^4 = 6x^3 - 8x^2

comes out unbalanced. what is the ^ representing?

if I compute it to a common 120x and multiply the others accordingly, it's like 16 = 30 in the end. I'd like to help.

Answer 4

15x^5 - 20x^4 = 6x^3 - 8x^2 1st factor out x^2
15x^3-20x^2=6x-8
15x^3-20x^2-6x+8=0
from here you can try synthetic division.
possible factors are:
x+/-1
x+/-2
x+/-4
& x+/-8
you could also try pluging #'s in or use a numerical method such as newton raphson.
I couldn't find any integer answers. I would try Newton Raphson

Answer 5

THIS IS SURELY THE BEST EXPLAINED ANSWER:

15x^5 - 20x^4 = 6x^3 - 8x^2

x^4(15x-20)=x^2(6x-8)

x^4(15x-20) - x^2(6x-8) = 0
x^2 ( x^2(15x-20) - (6x-8) ) = 0
This implies that:
either x^2 = 0, which means x=0

or x^2(15x-20) - (6x-8) =0

15x^3 - 20x^2 - 6x + 8 =0

On solving this, you will get the following values:
x=0(two values)
x=79/125
x=4/3
x= - 4/3
this makes the total values 5 ( the original eqn. was of degree 5) and hence there is your soln.!!!

Answer 6

well Dear nejnej....
15x^5 - 20x^4 = 6x^3 - 8x^2

● Part 1
15x^5 - 20x^4
{ Factor " 5x^4" }
5x^4 ( 3x - 4)

● Part 2
6x^3 - 8x^2
{ Factor " 2x^2" }
2x^2 ( 3x - 4 )

● Part 3
5x^4 ( 3x - 4) = 2x^2 ( 3x - 4 )
{ simplify " 3x - 4 " }
5x^4 = 2x^2
5x^4 - 2x^2 = 0
{ factor " x^2 " }
x ^2 ( 5x^2 - 2 ) = 0
x ^2 = 0 , x = 0
5x^2 - 2 = 0
x = - √(2/5)
x = + √(2/5)

so we have 3 real; solutions
x = 0
x = - √(2/5) = - 0.63246
x = + √(2/5) = + 0.63246

Good Luck Darling ♣

Answer 7

15x^5-20x^4-6x^3+8x^2 = 0
15x^3-20X^2-6x+8=0

That's all i'll do for you

Answer 8

Leah H is solution is correct, the Hidden Truth solution is wrong. Leah H is missing 0 thus,

1)negative square root of (2/5) = -0.63
2) 0
3)positive square root of (2/5) = 0.63
4)4/3 = 1.33

Use ruffini method, after simplification of polynomial.

Answer 9

i dont thick the term "fairly" is valid in physics. each and every component interior the international i discovered to be relative. So regardless of if some one million isn't good, he could be good 4 u if he's able to reply to your question satisfactorily. So toddler, atleast ask a query.

Answer 10

You need to bring all the numbers to one side (set them equal to zero) and work on distributing from there.