the dimension of the cuboid is 20cm by 8cm by 25mm.if thegold is recast into a cylinder of diametre 2mm what is the length of the wire
2006-10-30 06:05:25 · 4 answers · asked by Olaniyi s 1 in Science & Mathematics ➔ Physics
19355kg/m^3=19.355g/cm^3
20*8*25=4000cm^3
19.355g/cm^3*4000cm^3=77,420g=77.42kg
d=.2cm A=pi*.1^2=.01*pi=.0314cm^2
4000cm^3/.0314cm^2=127324cm=127.32m
2006-10-30 06:15:56 · answer #1 · answered by yupchagee 7 · 16⤊ 0⤋
Put the cm measurements into metres then multiply them together to get cubic metres, then multiply the answer by 19355 to get the answer in kg.
Do the same for the second part, recognising that 2mm is 2/1000 metre. That's the diameter, so the radius is half that and the cross-sectional area is pi+r^2.
2006-10-30 06:16:32 · answer #2 · answered by JJ 7 · 0⤊ 0⤋
To begin with the density doesn't matter.
Convert every thing into mm and compute the volume of the cube
divide the volume by the cross section(sq mm) of the 2mm wire and that is the length of wire you get.
2006-10-30 06:15:29 · answer #3 · answered by Sophist 7 · 0⤊ 0⤋
40 kg - 2.4 km
2006-10-30 06:16:55 · answer #4 · answered by Steve C 3 · 0⤊ 0⤋