one mole of oxalic acid(h2c2o4) is equivalent to ___moles of permanganate(MnO4)
1. 1
2. 2
3. 2/5
4. 5/2
2006-10-30 05:50:13 · 4 answers · asked by Shawn 1 in Science & Mathematics ➔ Chemistry
Just look at the BIG numbers before each compound/ion.
5 molecules of oxalic acid react with 2 molecules of MnO4, so 1 mole of oxalic acid (divide by 5)reacts with 2/5 moles (divide by 5) MnO4.
2006-10-30 05:54:15 · answer #1 · answered by JJ 7 · 1⤊ 0⤋
2/5
2006-10-30 06:01:25 · answer #2 · answered by DR. WHO 3 · 0⤊ 0⤋
3. 2/5
2006-10-30 05:52:29 · answer #3 · answered by Geo06 5 · 0⤊ 0⤋
First be certain the form of moles of KMnO4 you have 0.025molesKMnO4 x 0.03345L= .....1Liter.KMnO4 =8.6x10-5moles KMnO4 thinking the mole to mole ratio is 5 moles Oxalic acid to 2 moles of the permanganate ion then you definately've: 8.6X10-5*(5/2)= 2.15x10-4 moles Oxalic acid Now convert to grams employing the molar mass of oxalic acid 2.15x10-4moles OA x ninety.0354g OA= ......................................... mole OA (one million.9x10-2g Oxalic acid/8.40 two)*a hundred=0.23%
2016-11-26 19:33:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋