2006-10-30 05:35:58 · 4 answers · asked by someone 1 in Science & Mathematics ➔ Mathematics
I wanted to mean, that "n" is part of the set of the natural numbers (not including the 0).
2006-10-30 05:42:58 · update #1
I still hope, that theer will be someone to tell me the answer, and the solving method too :).
2006-10-30 05:44:37 · update #2
This is not a series. This is the ratio between the sewquence of partial sums of 3^(n-1) and 9^n.
For every n=1,2,3..... 1 + 3 + ........3^(n-1) = (3^n -1)/(3 -1) = (3^(n-1))/2. This is the sum of the the first n terms of a geometric progression.
Therefore, a(n) = (3^n - 1)(2 * 9^n) =(1/2) * ((1/3)^n - 9^(-n)).
If n-> oo, then (1/3)^n -> 0 and 9^(-n) -> 0. Therefore, lim a(n) 1/2 * 0 = 0.
2006-10-30 05:43:26 · answer #1 · answered by Steiner 7 · 0⤊ 0⤋
Hello,
For these types of questions, Yahoo! Answers is not the site.
Better you may check with Google Answers. It's a paid service but you get serious answers with sincere research results. Sometimes, they include the history of equations too!
As per my knowledge, this site is just an entertainment for people and not for receiving research style answers. But still there are people who give good answers here. Good luck!
2006-10-30 05:40:29 · answer #2 · answered by Nirmal Natarajan 2 · 0⤊ 0⤋
I'm not sure I'm reading the function correctly... I'm with you up until the comma.
If you exclude everything after the comma, the limit of a(n) as n approaches infinity would be 0 (zero), but I am not sure where "n e N*" fits in, nor what it means.
Sorry.
2006-10-30 05:40:22 · answer #3 · answered by disposable_hero_too 6 · 0⤊ 0⤋
look in the back of the text book
2006-10-30 05:36:49 · answer #4 · answered by Juleette 6 · 0⤊ 0⤋