2006-10-30 04:06:20 · 4 answers · asked by veronica r 1 in Science & Mathematics ➔ Chemistry
I'm guessing that you mean that you have 100lb of solution which is 99% water then some of the water is evaporated until you have solution which is 98% water; then what is the weight of the result?
In this case, you have 1lb of stuff along with 99lb of water to give 99% water. Then you let the water evaporate until you have x lbs of water left. Then the percentage of water in the solution would be amount of water over the total amount of solution:
x / (1 + x) = .98,
which then you can solve for x=49. So you have a total of 1+49 = 50 pounds of solution left.
2006-10-30 04:40:23 · answer #1 · answered by bag o' hot air 2 · 1⤊ 0⤋
your question makes no sense!! if 100 lbs contains 99% water and now is 98% water then it is still 100 lbs because in the first place there is 1% of non water stuff , while in the second pllace there is 2% of non water stuff . so there is a trade off and the weight should not be too far different. the only way to know is to find out what is the density of the non water stuff.
God bless,
gabe
2006-10-30 04:18:42 · answer #2 · answered by gabegm1 4 · 0⤊ 0⤋
99 lbs
2006-10-30 04:45:04 · answer #3 · answered by source_of_love_69 3 · 0⤊ 0⤋
It depends on what the other 1% is.
2006-10-30 04:17:21 · answer #4 · answered by Anonymous · 0⤊ 0⤋