-(3+x) <2 (3x-5)
I can graph it fine, but I'm having a real brain fart on solving this question.
2006-10-30 01:57:08 · 4 answers · asked by Nate C 1 in Science & Mathematics ➔ Mathematics
-3-x<6x-10
-7x<-7
7x>7
x>1
so draw the line x=1
i.e. line parallel to the y axis
at a distance of 1 unit from the origin
and shade the portion of the right of the line
2006-10-30 02:09:32 · answer #1 · answered by raj 7 · 0⤊ 1⤋
don't worry , after solving 10000 of these every one feels as an expert !! here we go :
-3-x < 6x-10
-7x<-7
the point is here : x>1 !!( the reason is this : imagine the x<1 then put and example digit in the equation for example -7*0<-7 !! you know it is wrong . right ? )
and that's it . then you can mark all the right side of the graph after x=1 !
have fun !
2006-10-30 12:45:32 · answer #2 · answered by arash 3 · 0⤊ 1⤋
-(3 + x) < 2 (3x - 5)
Expand the brackets:
-3 - x < 6x - 10
Add 10 to both sides
7 - x < 6x
Add x to both sides:
7 < 7x
Divide both sides by 7:
1 < x
-> x > 1
2006-10-30 10:05:24 · answer #3 · answered by turkeyphant 3 · 0⤊ 0⤋
Remove parentheses from both sides:
-3 - x < .......
Then add x to both sides and add 10 to both sides.
Now divide both sides by 6 and you should get
......... < x
which is the same as
x > ........
THEN you can do a number line graph showing that x is greater than this value which I'm sure you can find for yourself.
2006-10-30 10:06:35 · answer #4 · answered by Hy 7 · 0⤊ 1⤋