I need some help with Linear Equations...?

Question

Find the missing values that solve this equation.

1. y = 3x
(0, ____) (-1,____) (7,____)

2. y = 5 -4x
(5, ____) (1, ____) (-1, ____)

3. 2x+y = 6
(2,____) (0,____) (1,____)

Answer 1

Hi Darling

lol b4 i open you question i thought am the first one . but it seems ppl were faster than me . so as all of them are CORRECT ,So i don't repeat the correct answer.
hope next time i can be the first.

Good Luck sweetheart ♣

Answer 2

All you need to do is change X to the number they give you. The three things in parenthesees are all in (x,y) format, so the first number is what X is, and the second number is what Y is. In every problem here, they give you X and make you solve for Y.

The very first problem for instance, you want to say "what would Y be if X equals 0.
y = 3x
if X equals zero, then 3*0 = 0, so y = 0

answers
1. 0, -3, 21
2. 15, 1, 9
3. 2, 6, 4

Answer 3

to find the values just substitute x value in equation
1. y=3x
(0,0) , ( -1, -3) , (7, 21)

2. y= 5-4x
(5, -15) , (1, 1) , (-1, 9)

3. 2x+y =6 ===>> y= 6-2x
(2, 2) , (0, 6) , (1, 4)

Answer 4

1. 0, -3, 21

2. -15, 1, 9

3. 2, 6, 4


Technique: the first number in the brackets represent x, so, just substitute the valur of x into the equation and you can find the value of y which is represented by the 2nd number in the brackets that you need to find.

Answer 5

1. (0,0), (-1,-3), (7, 21)
2. (5, -15), (1, 1), (-1, 9)
3. (2, 2), (0, 6), (1, 4)

Answer 6

1. y = 3x
(0, 0) (-1,-3) (7,21)

2. y = 5 -4x
(5, -15) (1,1) (-1,9)

3. 2x+y = 6
(2,2) (0,6) (1,4)

Answer 7

1] 0,-3,21
2]-15,1,9
3]2,6,4