0.3500 grams of oxalic acid will react with how many mL of 0.100 M permanganate solution?

Question

According to the balanced chemical equation

5H2C2O4(aq) + 2MnO4(aq) + 6H+(aq) -----> 10CO2(g) + 2Mn2+(aq) + 6H2O(l)

a.) 15.5
b.) 38.9
c.) 77.7
d.) 97.2


please show work

Answer 1

moles MnO4(-)= M*V=0.1*V

The MW of oxalic acid is 90. So according to the reaction

5*90 gr oxalic acid react with 2 mole permanganate
0.35 gr oxalic acid react with 0.1*V

Therefore 5*90*0.1*V= 2*0.35 => V=0.7/45= 0.0155 L=15.5 mL