I need to solve these equations, please help:?

Question

They already look solve to me??

Solve √x + 4 = 3


Solve √4x + 1+ 3 = 0



Solve √2x + 7 + 4= y

Answer 1

To solve, you need to find x.

1.) √x + 4 = 3
√x + 4 - 4 = 3 - 4
√x = -1

No answer for this one: √x can never equal a negative number.

If you meant: √(x + 4) = 3, then:
√(x + 4)^2 = 3^2
x + 4 = 9
x + 4 - 4 = 9 - 4
x = 5

2.) √4x + 1+ 3 = 0
√4x + 1+ 3 - 1 - 3 = 0 - 1 - 3
√4x = -4
2√x = -4
2√x / 2= -4 / 2
√x = -2

Again, no answer for this one: √x can never equal a negative number.

Even if you meant √(4x + 1) + 3 = 0, you'd have √(4x + 1) = -3, which can't occur.

3.) √2x + 7 + 4= y
√2x + 7 + 4 - 11= y - 11
(√2x) ^2 = (y - 11) ^2
2x = (y-11)^2
x = (y-11)^2 / 2

Answer 2

1) x = (3 - 4) (3 - 4)
x = (-1) x (-1)
x = 1

2) 4x = (- 3 - 1) (- 3 - 1)
4x = (-4) x (-4)
4x = 16
x = 4

3) 2x = (y - 3) (y - 3)
2x = (y x y) - 3y - 3y + 9
x = (y x y) - 6y + 9

Since, (y - 3) = 0
y = 3

Substitute: x = (3 x 3) - 18 + 9
x = 0

Hey i'm not really sure of the last one...