y=1/3(x-2)
3y=x-2
3y+2=x
so
x=3y+2
2006-10-29 23:50:25
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answer #1
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answered by safrodin 3
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y=1/3(x-2)
y=x/3 - 2/3
y+2/3=x/3
x/3= y+2/3
x=3(y+2/3)
x=3y +3*2/3
x=3y+2
2006-10-29 23:56:12
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answer #2
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answered by MY Regards to All 4
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y=1/3(x-2) so solve for x. divide (or multiply by 3/1) each side by 1/3 so you get 3y=x-2.
then add two and you get 3y+2=x or x=3y+2
2006-10-30 00:44:25
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answer #3
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answered by horslover10 2
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Multiply both sides by 3(x-2):
3y(x-2) = 1
Now divide both sides by 3y, and then add 2 to both sides, and you have your answer! And you'll find that safrodin is not quite right.
2006-10-29 23:52:09
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answer #4
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answered by Hy 7
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y=1/3[x-2]
x-2=3y
x=3y+2
2006-10-30 00:29:49
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answer #5
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answered by openpsychy 6
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y = 1/3( x -2)
3y = 1 * (x -2)
3y = x -2
3y + 2 = x
2006-10-30 00:06:19
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answer #6
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answered by nanduri p 2
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X In Terms Of Y
2016-11-12 08:10:56
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answer #7
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answered by Anonymous
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y = 1/3 (x - 2)
3y = x - 2....................( times both sides with 3)
3y + 2 = x ........................(plus 2 to both sides)
Hence,
x = 3y + 2
I'm sure about it.
2006-10-30 00:19:49
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answer #8
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answered by AD 2
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Was looking for an answer on this too
2016-09-19 13:09:40
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answer #9
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answered by ? 4
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Was going to ask this too
2016-07-27 23:29:27
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answer #10
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answered by ? 3
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