2006-10-29 21:12:21 · 6 answers · asked by the honeythief 1 in Science & Mathematics ➔ Physics
there will be no change in the result because the equation shows no relationship G or g.
2006-10-29 21:37:22 · answer #1 · answered by chinmay 1 · 0⤊ 1⤋
You are only changing 'a' which, on earth
a=g=9.8ms-1
at zero gravity (true zero gravity - not the moon) g=0 therfore no force due to gravitational acceleration - but there may be another acceleration acting on the mass
Unsure as to what experiment - if you mean weight then weightless at zero gravity but you would still have mass
hope this kinda helps
2006-10-30 05:55:59 · answer #2 · answered by ? 2 · 0⤊ 0⤋
Acceleration stands for gravity when you compute for weight. So I'd say the first 2 answers are wrong. My answer would be, though, mass will remain but there will be no force to be exerted as you have no opposing force (gravity) to begin with. And it agrees with math: F=mass multiplied by zero... the answer would be zero. Ergo, no force present but only the existence of the mass of the matter.
2006-10-29 22:12:20 · answer #3 · answered by gameplan_xtreme 4 · 0⤊ 0⤋
The mass and acceleration will still have values
2006-10-29 21:17:21 · answer #4 · answered by monkey_flem 2 · 0⤊ 1⤋
exactelly the same thing
2006-10-30 00:08:36 · answer #5 · answered by Anonymous · 0⤊ 0⤋
It would be the same.
2006-10-30 00:34:11 · answer #6 · answered by Mark G 7 · 0⤊ 0⤋