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.Examine carefully the following sequence of numbers:
1
11
21
1211
111221
312211
13112221
1113213211
31131211131221
13211311123113112211
hint: ( in first row one 1, in 2nd row two 1s, in 3rd row one 1,........
Although the sequence appear to behave totally at random, In fact , after the first sequence, each sequence is constructed in a precise and methodical way based on the previous one. What is the next sequence?

a)11322212311233113232211211 b)11131221133112132113212221
c)11131221133112221132122211 d)11131221133312112211321222

2006-10-29 21:00:17 · 6 answers · asked by sweetu 1 in Science & Mathematics Mathematics

6 answers

The answer is (b) 1113122113311213211212221

Well, while your observation that the sequence has been constructed in a precise and methodical way, may be true, I have analysed on logic. After the first row see the last two digits of the nos. they are 11,21,11,21,11,21 repetitively. The no. in the last row given by you has last two digits as 11 and so the number in the sequence has to have the last two digits as 21 as per me. In the options given there is only one such number. and that is (b).

This is my solution and reasoning for it!!!

2006-10-29 21:41:38 · answer #1 · answered by Manindomb 2 · 0 0

excellent ive got it. the sequence is how many of the previous numbers there are. so theres 1 then 11 because there is 1 1. then 21 because before that there are 2 1s
then its 1211 because there is 1 2 and 1 1. ect so if the number was 123 the next number would be 111213 because there is one 1, one 2 and one 3. so the awnser is b. if u not get it email either send me a message on here or email me on dnegel2006@hotmail.com. good luck

2006-10-29 21:35:49 · answer #2 · answered by dnegel2006 2 · 0 0

1
11
21
1211
111221
312211
13112221
1113213211
31131211131221
13211311123113112211
11131221133112132113212221

The answers is B

1 - 3 - 2 - 11 - 3 - 111 - 2 - 3 - 11 - 3 - 11 - 22 - 11
(1)1 - (1)3 - (1)2 - (2)1 - (1)3 - (3)1 -(1)2 -(1)3 -(2)1 -(1)3 -(2)1-(2)2-(2)1



see from top 1 the number in the bracket is occurance/s following by the number it self

1
(1)1
11
(2)1
21
(1)2-(1)1
1211
(1)1-(1)2-(2)1
111221
(3)1-(2)2-(1)1
312211
(1)3-(1)1-(2)2-(2)1
13112221
(1)1-(1)3-(2)1-(3)2-(1)1
1113213211
(3)1-(1)3-(1)2-(1)1-(1)3-(1)2-(2)1
31131211131221
(3)1-(1)3-(1)2-(1)1-(1)3-(1)2-(2)1
13211311123113112211

2006-10-30 00:01:43 · answer #3 · answered by safrodin 3 · 0 0

A = 11322212311233113232211211

2006-10-29 21:03:16 · answer #4 · answered by Anonymous · 0 0

11131221133112132113212221 ... answer is b and dnege got the idea perfectly!!! I just tested it!!!

Well done dnege!!!!!

2006-10-29 21:41:52 · answer #5 · answered by Wal C 6 · 0 0

b).

2006-10-29 22:11:24 · answer #6 · answered by openpsychy 6 · 0 0

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