what is the original number?
2006-10-29 17:29:31 · 17 answers · asked by charms 1 in Science & Mathematics ➔ Mathematics
3x-14=(2/3)x
x=6
2006-10-29 17:33:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The original number is 6
2006-10-29 20:58:41 · answer #2 · answered by cooldude 3 · 0⤊ 0⤋
Let the original number be x.
1. Triple the number: 3x
2. Subtract 14: 3x-14
3x-14= 2x/3 (mulitply both sides by 3)
9x-42= 2x (Subtract 2x from both sides)
7x-42=0 (Add 42 to both sides)
7x =42 (Divide both sides by 7)
x =6
2006-10-29 18:54:15 · answer #3 · answered by lee-wlcj 2 · 0⤊ 0⤋
3x - 14 = 2x/3
9x - 42 = 2x
7x = 42
x = 6
To check, 3*6 - 14 = 18 - 14 = 4, and 4 is 2/3 of 6
2006-10-29 17:35:58 · answer #4 · answered by wild_turkey_willie 5 · 0⤊ 0⤋
That equation would look like this:
3X-14=2x/3
Multiply both sides by 3 to get rid of the fraction, so it's
9x-42=2x
Now put all X's on one side, and the rest on the other: say by subtracting 9x form both sides:
-42=2x-9x, or -42=-7x
-42/-7=6=x
X is 6
2006-10-29 17:33:24 · answer #5 · answered by Coop 3 · 0⤊ 0⤋
Let the no. be N. Now triple of the no. is 3N and two thirds of the no. is 2/3*N
So by the given condition we get, 3N - 14 = 2/3*N
i.e. 9N - 42 = 2N.
Therefore 7N = 42. Hence N = 42/7 = 6
The original no. is 6
2006-10-29 21:29:08 · answer #6 · answered by Manindomb 2 · 0⤊ 0⤋
axccording to the given question
3n- 14= 2n\3
therefore, 3(3n-14)= 2n
9n- 42= 2n
7n= 42
n=6
hence the original number is 6
2006-10-29 17:36:20 · answer #7 · answered by GREY MATTER 2 · 0⤊ 0⤋
3x-14=2x/3 x=42/7=6
2006-10-29 18:31:23 · answer #8 · answered by peterwan1982 2 · 0⤊ 0⤋
let
n be the original number
Solution:
3n - 14 = 2/3n
3n - 2/3n = 14
(9n - 2n)/3 = 14
7n/3 = 14
7n = 42
n = 6
2006-10-29 17:38:47 · answer #9 · answered by Diwata 1 · 0⤊ 0⤋
Triple A Number
2017-03-01 10:57:49 · answer #10 · answered by ? 4 · 0⤊ 0⤋
3x - 14 = 2/3*x
x = 6
2006-10-29 17:34:54 · answer #11 · answered by teacher2006 3 · 0⤊ 0⤋