Approximately 30% of the calls to an airline reservation phone line result in a reservation being made.
a. Suppose that an operator handles 10 calls. What is the probability that none of the ten calls result in a reservation?
b. What assumption did you make to calculate the probability in Part (a)?
c. What is the probabililty that at least one call results in a reservation being made?
2006-10-29 15:59:53 · 3 answers · asked by portuguesechick89 2 in Science & Mathematics ➔ Mathematics
a: There is a 70% chance that no reservation will be made on a particular call, so the odds that no reservation is made on any of the calls is (.7)^10, which is 2.82475249% (exactly).
b: That the probability of a reservation being made on any particular call is equal to the probability of a reservation being made on any other particular call
c:1-2.82475249%, or 97.17524751%
2006-10-29 16:05:54 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
This is a binomial distribution. That is the event either occurs or does not and there are only 2 choices, like flipping a coin it is either heads or tails. That being said the probablity of the event occuring is p=.3 and the probablity of the event not occuring is q= 1-p = 1-.3=.7
a) you want all of the choices to be the event did not occur so you hae q^n or .7^10
b) read the above paragraoh
c) to find the probability of at leat one then find the probablity of none fromo a and subract that from one, as total probablity will always be one. All you need is a calculator and you will have all 3 answers.
2006-10-30 00:06:24 · answer #2 · answered by Anonymous · 1⤊ 0⤋
b. Another assumption is that the 30% rate also applies to this particular operator. In reality, some operators may be better than others... This particular one may have been the Employee of the Month for years in a row and got a 50% success rate, for all we know.
2006-10-30 10:22:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋