what is the limit x-> 0 of sqrt(x)??
2006-10-29 15:36:49 · 3 answers · asked by aznskillz 2 in Science & Mathematics ➔ Mathematics
Zero.
To the chainsmoking guy: actually, the left-hand limit does exist, and is equal to zero, if you permit the outputs of the function to be complex numbers. And if you don't, it is unecessary to consider the left-hand limit to find the limit, since the numbers on the left side would not then be in the domain of the function. In either case, the limit of the function is still zero.
2006-10-29 15:39:00 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
Since if you plug x=0 and you don't get a crazy "divide by zero" or infinity answer you can just take that value as the limit.
so sqrt(0) = 0
2006-10-29 15:41:06 · answer #2 · answered by munkmunk17 2 · 0⤊ 0⤋
the limit taken as x approaches 0 from the positive side is zero. taken from the negative side of zero, the limit does not exist.
2006-10-29 15:43:43 · answer #3 · answered by ChainSmokeKansasFlashDance 4 · 1⤊ 0⤋