I want a website, i already know of teenfreeway, i'm not going to google it. it has 2 be free,and im not going 2 the mall.
2006-10-29 15:12:12 · 9 answers · asked by Violet 1 in Beauty & Style ➔ Makeup
I received free samples from a great mineral makeup company called Everyday Minerals. I love their products and they don't make you break out. http://www.everydayminerals.com/shop/prod_80.html
2006-10-29 17:00:43 · answer #1 · answered by Anonymous · 0⤊ 0⤋
I know that Sephora gives samples at the store. But you are too lazy to go to the mall. Perhaps they give freebies online? Hmm, how could they keep track of all the free makeup being shipped out (cost of makeup plus shipping fees = too expensive)
Huh, maybe you will need to go to the store after all. If you find a place, please share it with the world for millions of women would love to know.
2006-10-29 15:18:35 · answer #2 · answered by altruisticind 2 · 0⤊ 0⤋
Violet, a really great way to get personalized service is go to marykay.com; put in your zip code and find a Mary Kay consultant near you. She will be your personal advocate for good skin care and working with you to find the best eye, cheek and lip colors! As always, 40+ years, MK consultants have samples and will be more than happy to let your try on colors to make sure you are happy! The customer service cann't be beat!
2006-10-29 15:49:50 · answer #3 · answered by deb 1 · 0⤊ 0⤋
Out of Cosmopolitan, Glamour magazine etc.
2006-10-29 19:36:09 · answer #4 · answered by Bu Tran 6 · 0⤊ 0⤋
Department store make up counters...just ask...
2006-10-29 15:17:44 · answer #5 · answered by Laura S 3 · 0⤊ 0⤋
i saw some on saphora.com, but i'm not sure if they still have any....you can check though
2006-10-29 16:04:06 · answer #6 · answered by purplepup220 2 · 0⤊ 0⤋
i did not know people did that!
2006-10-29 15:16:09 · answer #7 · answered by randaroo87 4 · 0⤊ 0⤋
why don't u just buy some?
2006-10-29 15:15:41 · answer #8 · answered by Anonymous · 0⤊ 0⤋
www.marykay.com/kmicek
2006-10-30 17:26:34 · answer #9 · answered by kelbell 3 · 0⤊ 0⤋