i have 7,000 Li of a solution of pH = 2.0. i want to raise it's pH to pH = 7.0 with 40% NaOH solution. i've calculated that about 4.7 Li of the caustic solution must be added. is this correct? how do you solve such a problem? thanks.
2006-10-29 14:45:48 · 3 answers · asked by lucky_me25 1 in Science & Mathematics ➔ Chemistry
Do you know what is in the pH 2 solution that you wish to neutralize? If it is buffered, then you will need more NaOH than if it is unbuffered.
2006-10-29 14:50:25 · answer #1 · answered by WildOtter 5 · 1⤊ 0⤋
Well, you want to change an acid solution to a neutral solution. Why? Then it becomes neither acid nor alkali. WHat is the point of the exercise. Your question.
Very very strong acid. ph 1-3.
Very strong alkali- concentrated bleach (sodium hypochrorite 40%)
That is a silly exercise. If all you wanted was diluted acid. Just dilute it down. with water into ph 6.0. The add a little bleach to further neutralize it to ph 7.0
2006-10-29 14:54:21 · answer #2 · answered by QuiteNewHere 7 · 0⤊ 0⤋
You really need to know what type of acid is causing pH of 2. If you can assume acid is very strong, totally discossiated, your answer could be right. If it is a weak acid or has two or more Hydrogens avalilable question gets more complex.
2006-10-29 14:55:14 · answer #3 · answered by steveSang 2 · 1⤊ 0⤋