how to factor these equations?

Question

1. 36y^2-60y+25
2. 15a^2b+22ab+8b
3. 64x^2-176xy+121y^2

Answer 1

You need to look at each one and determine how you can get them into the format of (A+B)(C+D) ... It really helps if you are familiar with the FOIL method of multiplying (A+B)(C+D) so that you can do some mental calculations to work backwards from the equations you have to the (A+B)(C+D) format that you're after when you are factoring.

OK, that being said, it would be pretty impossible to explain it further here, so I'll just give you the answers. Please try some of these on your own though so that you don't flunk your exams!

1. (6y-5)^2

2. b(5a+4)(3a+2)

3. (8x-11y)^2

~ ♥ ~

Answer 2

1) This is a perfect square: (6y-5)^2 Take the aquare roots of the end terms and check if the middle term is twice the product of these. Whenever you see the end terms as perfect squares, alway chech the middle term this way.

2) First factor out b to get b*(15^a^2 + 22*a + 8); the polynomial factors are(3a+2)*(5a + 4), so the factors are:
b, 3a+2, 5a+4

3) The polynomial is a perfect square. (8x - 11y)^2

Answer 3

(1) 36y^2-60y+25=(6y)^2-2*6y*5+(5)^2=(6y+5)^2 ans. (2)15a*2b+22ab+8b= b(15a^2+22a+8)= b(15a^2+10a+12a+8) = b{5a(3a+2)+4(3a+2)}=b(3a+2)(5a+4) ans. (3)64x^2-176xy+121y^2 =(8x)^2-2*8x*11y+(11y)^2 =(8x+11y)^2 ans.

Answer 4

That's really easy.

1. (6y-5)(6y-5) or, more specifically (6y-5)^2.

2. b(5a+4)(3a+2)

3. (8x-11y)^2

Sorry, but why don't you know already?