2006-10-29 12:18:45 · 3 answers · asked by ^*({K})r3My~(S)$yn luv$2play 1 in Science & Mathematics ➔ Mathematics
Well, your formula for the nth term should have 'n' in it, right? So, for the 101st term, just substitute 101 for each 'n' then solve.
Same for 20th term -- substiute 20 for each 'n' then solve.
Same for 30th term -- substiute 30 for each 'n' then solve.
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2006-10-29 12:20:21 · answer #1 · answered by I ♥ AUG 6 · 0⤊ 0⤋
Arithmetic sequences follow the form c + kn, where c and k are constants. For example, the sequence 1, 2, 3 ... is 0 + 1n, so that 1 is the first number in the sequence, two is the second etc.
The 101st term of an arithmetic sequence is c + 101n.
The 20th term is c + 20n.
The 30th term is c + 30n.
2006-10-29 12:24:30 · answer #2 · answered by Steve A 7 · 0⤊ 1⤋
The formula is an = a1 +(n-1)r where
an is the nth term
a1 is the first term
n is the number of term
r is the ratio... or increment
So: a101 = a1 + 100r ; a20 = a1 + 19r; a30 = a1 + 29r
To obtain numbers as result we must know the sequence, that is, the first term and the increment.
2006-10-29 12:54:25 · answer #3 · answered by vahucel 6 · 0⤊ 0⤋