3^2x=5 please help
2006-10-29 12:01:13 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
buy a ti-89. it's faster that way. if u need to show work, you gotta use the "log" method.
2006-10-29 12:03:46 · answer #1 · answered by Jeffrey W 3 · 0⤊ 0⤋
x = 5/9
2006-10-29 20:03:04 · answer #2 · answered by f1avor_f1av 3 · 0⤊ 0⤋
3^2 = 9
9x = 5
x =5/9
2006-10-29 20:03:07 · answer #3 · answered by hagbard73 2 · 0⤊ 0⤋
Use logarithms.
log(3^(2x)) = log(5) = 2x * log(3)
2x = log(5)/log(3)
2006-10-29 20:05:47 · answer #4 · answered by AnswerMan 4 · 1⤊ 0⤋
I agree with answerman, just some addition, x is around 0.7326
2006-10-29 20:27:27 · answer #5 · answered by Tingkatan3 3 · 0⤊ 0⤋
3^(2x) = 5
2x * ln(3) = ln(5)
2x = (ln(5))/(ln(3))
x = (ln(5))/(2ln(3))
x = (ln(5))/(ln(3^2))
x = ln(5)/ln(9)
ANS : (ln(5))/(2ln(3)) or (ln(5))/(ln(9))
2006-10-29 23:15:31 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋