Can I get some help with this long division problem?

Question

Use Long Division to find the quotient and remainder of:

x^4 + 5x^3 -21x -32 / x^2 - 3

Thank you

Answer 1

First take x^2 multiplied by the divisor

Then you have:
. x^4 + 5x^3 -21x -32
- x^4 - 3x^2

For a remainder of:

5x^3 + 3x^2 - 21x -32

Now take 5x as your next number (you always want to use a number that, when multiplied by the divisor, will let you get rid of the first term of what you are dividing into)

Then you have:
. 5x^3 + 3x^2 - 21x -32
- 5x^3 - 15x

For a remainder of:

3x^2 - 6x - 32

Now take 3 as your next number.

Then you have:
. 3x^2 - 6x - 32
- 3x^2 - 9

For a remainder of:

-6x - 23

So, your answer is x^2 + 5x + 3, with a remainder of -6x-23

(showing long division on YA is hard!)

~ ♥ ~

Answer 2

(x^4 + 5x^3 - 21x + 32) / (x^2 - 3)

x^2 (x^2-3) = x^4 - 3x^2

Subtract leaves:

5x^3 + 3x^2 -21x -32

5x(x^2-3) = 5x^3 -15x

Subtract leaves:
3x^2 - 6x -32

3(x^2-3) = 3x^2 -9

Subract leaves:
-6x -23

Quotient is x^2 +5x + 3
Remainder is -6x - 23

Answer 3

x^4+5x^3-21x+32/x^2-3:

x^4+5x^3+0x^2-21x+32/x^2-3=

x^2+5x+3+(-6x-23/x^2-3)

I hope this helps!

Answer 4

quotient: x^2 +5x +3
remainder: -6x -23

Answer 5

it is a little bit hard.