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The circumference of a sphere was measured to be 77 cm with a possible error of 0.8 cm. Use differentials to estimate the maximum error in the calculated surface area.

2006-10-29 11:12:17 · 2 answers · asked by Lionheart12 5 in Science & Mathematics Mathematics

The circumference of a sphere of radius r is C=2pi*r, and its surface area is 4pi*r^2.

2006-10-29 11:19:46 · update #1

2 answers

C = 2πr, r = C/(2π)
A = 4πr^2 = 4π(C/(2π))^2 = (1/π)C^2
dA/dC = (2/π)C
dA = (2/π)CdC
dA = 2(77)0.8)/π
dA = 39.215 cm^2

Check:
A = (1/π)((77.8^2 - 77^2) = 39.419cm^2

2006-10-29 11:41:07 · answer #1 · answered by Helmut 7 · 0 0

C = 2πr
dC = 2πdr
Thus δC ≈ 2πδr
± 0.8cm ≈ 2πδr
δr = ± 0.8/2πcm
= ± 0.4/πcm

S = 4πr²
dS = 8πrdr
So δS ≈ 8πrδr
= 8π * 77 * ± 0.4/π
= ±1540 cm²

2006-10-29 11:28:15 · answer #2 · answered by Wal C 6 · 1 0

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