Triangle inequality says that any side of a triangle is less than the sum of the other two sides.
Clearly in this triangle the longest side can either be 25 or the missing side
Let its length be ℓ
Then either 25< ℓ + 6 or ℓ < 25 + 6
ie 25 - 6 < ℓ < 25 + 6
19 < length of 3rd side < 31
2006-10-29 11:14:08
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answer #1
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answered by Wal C 6
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If the triangle is very nearly a straight line with the 6 side lying nearly against the 25 side, the third side would have to be almost (but not quite) 25-6=19. If it's again very nearly a straight line with the 6 side rotated to point away from the 25 side, the third side could be almost (but not quite) 25+6=31. 19
The third side couldn't equal 19 or 31 because then it wouldn't be a triangle, it would be a straight line.
2006-10-29 11:18:43
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answer #2
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answered by Anonymous
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try visualising the extreme values.
If the 3rd side were 19, the so called triangle would have squashed into a straight line, as 6 + 19 = 25
similarly, if the 3rd side were 31, a straight line would be formed as 6 + 25 = 31.
So the 3rd side of the triangle must be greater then 19 and less than 31
2006-10-29 11:21:17
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answer #3
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answered by rosie recipe 7
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0 to 31
2006-10-29 11:13:13
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answer #4
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answered by ash v 3
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The 0.33 component can't be better than the sum of the two facets 6 + 25 = 31 The 0.33 component can't be much less that the version of the two facets 25 - 6 = 19 the respond is nineteen
2016-11-26 02:27:21
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answer #5
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answered by ? 3
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the range ofpossibilities for the third side should be
25-6
(19,31)
2006-10-29 11:54:21
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answer #6
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answered by peterwan1982 2
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It's got to be between 19 and 31.
2006-10-29 11:22:27
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answer #7
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answered by DavidNH 6
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It has to be longer than 25-6, and shorter than 25+6
2006-10-29 11:14:28
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answer #8
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answered by Ken H 4
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I'm not sure what the question really is, but if you want the length of the third side, it's about 25.7
2006-10-29 11:30:55
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answer #9
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answered by Anonymous
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Quit Tryin to Get answers to your Homework on Yahoo!
2006-10-29 11:18:26
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answer #10
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answered by GoBlue!MikeHart! 2
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