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The coin starts with an initial angular speed od 56.2 rad/s and rolls in a straight line without slipping. The acceleration of gravity is 9.8 m/s^2. How far does it roll up the inclined plane (answer in m)?

2006-10-29 11:07:01 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

diameter of coin=2.04cm=.0204m
radius of coin,r=.0204/2=.0102m

angular speed =56.2 rad/s
linear speed =ang. speed*r
=56.2*.0102
=.57m/s

a=v^2/r
=.57^2/.0102
=-31.37m/s(negative because coin is decelerating)

v^2-u^2=2as (v is the final speed=0; u is the initial speed)

0-.57^2=2*(-31.37)s
s=0.51m

2006-10-30 00:22:02 · answer #1 · answered by tul b 3 · 0 0

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