10 + 10 + 1
5 + 5 + 10 + 1
5 + 5 + 5 + 5 + 1
And there's more, if you take each of the above an rewrite the non-penny portion in terms of pennies. For example for the first one:
10 + eleven 1's
In this work, 1=penny, 5=nickel, 10=dime
I've started this for you and told you how you can find some more. I can't do your entire problem for you as I'd be robbing you of the learning experience. Please try to find some of the other answers on your own - it will be good practice for you.
~ ♥ ~
2006-10-29 11:01:09
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answer #1
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answered by I ♥ AUG 6
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21 Pennies
4 Nickles 1 Penny
2 Dimes 1 Penny
1 Dime 2 Nickels 1 Penny
2 Nickels 11 Pennys
1 Dime 11 Pennys
1 Nickle 16 Pennies
2006-10-29 11:08:57
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answer #2
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answered by Anonymous
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for 21 cents, you can have pennies, nickels and dimes.
1) 21 pennies
2) 16 pennies and one nickel
3) 11 pennies and 2 nickels
4) 6 pennies and 3 nickels
5) 1 penny and 4 nickels
6) 11 pennies and 1 dime
7) 1 penny and 2 dimes
8) 6 pennies, 1 nickel and 1 dime
9) 1 penny, 2 nickjels and 1 dime
that's it
2006-10-29 11:18:25
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answer #3
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answered by Anonymous
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It's not possible to describe them all.
Just on the one that involves the fewest coins, two dimes and a penny.... Have you any idea how many dimes and pennies are in circulation?
The number of combinations is practically infinite.
2006-10-29 11:03:44
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answer #4
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answered by open4one 7
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I came up with nine total combinations. I used "d" to denote dimes, "n" to denote nickles, and "p" to denote pennies. The combinations are as follows:
2d+1p
1d+2n+1p
1d+1n+6p
1d+0n+11p
4n+1p
3n+6p
2n+11p
1n+16p
0n+21p
2006-10-29 11:10:38
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answer #5
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answered by Richard H 7
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10, 10, 1
10, 5, 5, 1
10, 5, 6
10, 11
5, 5, 5, 5, 1
5, 5, 5, 6
5, 5, 11
5, 16
21 pennies
i think thats it
2006-10-29 11:04:11
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answer #6
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answered by kristin 3
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my advice is to do it yourself, because it isn't hard just time consuming
plus everyone here is too lazy to do it either (although there are exceptions, not to say that they are bad)
2006-10-29 11:02:19
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answer #7
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answered by Anonymous
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