Marneshia, who is 1.676 meters in height, stands at the base of the Eiffel Tower. Marneshia’s shadow at 2.5 meters is far shorter than the Eiffel Tower’s 412 meter shadow. What is the height of the Eiffel Tower, rounded to the nearest meter? Show all your work for credit.
2006-10-29 10:57:37 · 3 answers · asked by Roberta A 1 in Science & Mathematics ➔ Mathematics
By similar triangles
h(Mar) : h(Tower) = shadow(Mar) : shadow(Tower)
So 1.676 : h(Tower) = 2.5 : 412
Thus h(Tower) = 412/2.5 * 1.676
= 276.2048
= 276 m (nearest m)
2006-10-29 11:12:05 · answer #1 · answered by Wal C 6 · 0⤊ 0⤋
If h is the height of Eiffel tower then:
412/h = 2.5/1.676 so
h = 412*1.676/2.5 or h = 276 m approx.
2006-10-29 11:01:29 · answer #2 · answered by Dimos F 4 · 0⤊ 0⤋
1. Put it as a ratio.
1.676 to 2.5 as x to 412.
2. Cross-multiply.
2.5x = 690.12
3. Solve for x.
x = 276.2048 = about 276m
You're welcome!
2006-10-29 11:21:18 · answer #3 · answered by Anonymous · 0⤊ 0⤋