Consider a diatomic molecule oxygen, O2.?

Question

It is rotating in the xy plane about the z axis passing through its center, perpendicular to its length. The mass of each oxygen atom is 2.66 x 10^-26 kg, and at room temperature, the average separation distance between the two oxygen atoms is
2.02 x 10^-10 m (atoms treated as point masses). if the angular speed of the molecule about the z axis is 5.61 x10^12 rad/s, what is the rotational kinetic energy (answer in J)?

NEED MORE INFO PLEASE

Answer 1

E=mV^2=m(rw)^2 where w is angular speed and r=radius.
r=2.02 *10^-10 /2=1.01*10^-10
we have 2 atoms then

E=2*2.66*10^-26 *(1.01*10^-10 * 5.61 * 10^12 )^2
E=1.708 *10^-20 J