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What would the electric field look like for a negatively charged object near a conducting sheet?
In other words, if I have a negatively charged pipe brough close to a piece of aluminum what would the field look like between these two objects?

2006-10-29 10:27:58 · 2 answers · asked by crazed1511 1 in Science & Mathematics Physics

2 answers

What is the charge on the conducting sheet before you bring the pipe near? An electric field is determined by charge difference. If there is no charge difference then there is no field. Determine the direction of field flow. You can choose either positive to negative or negative to positive. The first people to do this didn't know any better. The lines will be straighter nearer the perpendicular distance between the sheet and the pipe. As you get further away, the lines from the pipe to the sheet will become more bent. The will move away from the pipe and "accelerate" toward the sheet in the direction of the sheet.

It will resemble field lines from a magnetic field. The difference is that the field lines from a magnetic field always form a complete circuit. The electric field lines are from point to point so to speak and do not form a complete circuit.

2006-10-29 10:40:12 · answer #1 · answered by Jack 7 · 0 0

anticipate the +5.7 is 25 cm to the left of the -3.5 cost. The 0.33 cost can't be to the left of the 5.7 because the 5.7 will continually provide a larger pressure than the three.5. It can't be in between both or that is going to continually get pushed to the left or the right so it would want to be to the right of the -3.5 cost. considering that pressure is proportional to cost over distance squared, placed 3.5/x^2 = 5.7/(x+25)^2 to stability the forces. each and every thing else cancels. confirm by technique of taking sq. roots of both part to get x(sqrt(5.7) = (x+25)sqrt(3.5) or 2.39x = a million.87x + 40 six.8 giving x = ninety cm

2016-12-05 08:41:16 · answer #2 · answered by mallie 4 · 0 0

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