Can someone in simple terms show me how i get 128 from 8[8+(2-1)*6+(3-1)]. I need a step ny step guide.?

Question

I used a calculator but need to know how to do it by multiplying out the bracets or using bodmas

Answer 1

Sure, I'll help you. You need to work on the interior parentheses first, then move to the outer. Also, you multiply before adding or subtracting. So here's the steps:

8[8+(2-1)*6+(3-1)]

First do the (2-1) and (3-1) to get the following:

8[8+(1)*6+(2)]

If there's only one thing in a parens, you can remove the parens:

8[8+(1)*6+2]

1 times anything is just that same anything, so you can remove the (1)* as follows:

8[8+6+2]

Now add up what's in the brackets, to get

8(16)

And now you just have 8 * 16 which is 128

Hope that helped!

~ & hearts; ~

Answer 2

First do the parentheses inside the brackets: (2-1)=1; (3-1)=2

Cross out the 2-1 and 3-1 and write these answers above the crossouts

Next inside the brackets do the multiplication: what is now 1 times 6 which is 6

Cross out the 1 and 6 and write 6 above

Now add all the things in the brackets: 8 + 6 + 2 is 16
Cross out all the stuff in the brackets and write 16 over it

Finally multiply 8 by 16 and get 128

Answer 3

The rule is to first work on the stuff inside the paranthesis. Once all the parenthesis are finished, work on the multiplication/division next and then finally the addition/subtraction.

So first step is to work on the parenthesis:
8[8+1*6+2]

Now you need to work out the stuff inside the brackets. Remember do the multiplication first:
8[8+6+2]

Now finish adding the numbers in the bracket
8[16]

And now you finish by multiplying the two numbers
8*16 = 128

Answer 4

do the bracket bit first i.e work out 2-1 and 3-1 giving
8[8+(1)*6+(2)]
then do 6*1=1 giving...
8[8+6+2}
then work out this bracket (BODMAS) giving...
8[16] = 8x16 = 128!

Answer 5

8[8+(2-1)*6+(3-1)] = 128
8[8+(1*6) + 2] = 128
8[8+6+2] = 128
8*16 = 128
Q.E.D

Don't know where EmLovePin is coming from. There's a problem with her maths.

Answer 6

8[8+(2-1)*6+(3-1)]
8[8+(2-1)*6+(2)]
8[8+(3)*6+(2)]
8[8+18+(2)]
8[28]