Can someone in simple terms show me how i get 128 from 8[8+(2-1)*6+(3-1)]. I need a step ny step guide.?

Question

I used a calculator but need to know how to do it by multiplying out the bracets or using bodmas

Answer 1

8[8+(2-1)*6+(3-1)]
= 8[8+(1)*6+(3-1)]
= 8[8+(1)*6+(2)]
= 8[8+6+(2)]
= 8[8+8]
= 8[16]
= 128

Answer 2

Its BEDMAS, not bodmas. Do the calculations in order of:

Brackets - simplify everything inside the brackets first. If there are multiple layers of brackets, work from the inside out.

Exponents - do any exponents (powers) nest

Division - do all division calculations next

Multiplication

Addition

Subtraction


Follow these steps, you can't go wrong.

step 1 - (2-1) = 1 (B)
step 2 - (3-1) = 2 (B)
step 3 - 1*6 = 6 (B&M)
step 4 - 8+6+2 =16 (B&A)
step 5 - 8*16 = 128 (M)

Answer 3

Using bodmas just go thru the steps

Brackets: You've got 2-1 = 1 and 3-1 = 2

This makes the calculation 8[8+1*6+2]

Next is multiply: 1*6 = 6

Now we've got 8[8+6+2]

Now add: 8+6+2 = 16

So now we've got 8[16]

Just multiply it out and you've got 128

Answer 4

BPEMDAS
BRACKETS
Let's tackle the stuff in the BRACKETS

In the brackets, we have parentheses

8[8+(1)*6+2]

No exponents in the brackets

Next multiply IN THE BRACKETS ONLY

8[8+6+2]

No division

Add in the brackets

8[16]

No subtraction

Now multiply by the term outside the bracket

8*16=128

Answer 5

2-1*6 =6
8+6=14
3-1=2
14+2=16
16*8=128

Answer 6

hello there. First of all (2-1) and (3-1) clearly simplify to 1 and 2 respectively. Hence, your expression reads 8[8 + 6 + 2] . This is therefore equal to 8x16 (where 16 is the sum of the terms inside the brackets). 8x16 = 128, and we're done.

Answer 7

The advice you have been given is excellent, please just don't copy one of the answers because you will get stuck again when you have to answer a similar question.

One final thing, you are correct to use the term BODMAS . You have not made a spelling mistake although BIDMAS or BEDMAS is now used.

BODMAS used to be used at school and the O stood for 'of.'
This was at a time when teaching INDICES or EXPONENTS did not come until later.

Answer 8

open up the inner brackets and simplify
8[8+1*6+2]
now simplify terms inside it
8[8+6+2]
8[16]
now multiply
8*16
128 ans

Answer 9

1)do what is between ( …. ), that is
(2-1) & (3-1) so now you have got 8[8+1*6+2]
2)now do 1*6 (multiplication & division must be done before addition & subtraction), so you have got 8[8+6+2]
3)now do what in between [ … ], so you have got 8*16, that is = 128
4)I do not use calculator, I prefer to use Excel, it can easily to cope with formulas like this!

Answer 10

(2-1)*6=1*6=6
(3-1)=2
8[8+6+2]=8*16=128