here is my complex number division-am I correct?

Question

5-6i/6-5i

perform the following complex number division and write it in standard form

I could only simplify, and came up with this:
-6i + 5 / -5t + 6
as my answer.

I don't think that it is divisable?
or am I even close?
HELP..I am confused today, more than ever!

If the answer is
1 i / -1 i

would that just be reducing it down? or solving it..

Answer 1

multiply top and bottom by 6+5i to get rid of the complex term in the denominator:

(5-6i) * (6+5i)
------------------------ =
(6-5i) * (6+5i)


30 - 36i + 25i - 30i^2
----------------------------- =
(6^2 - (5i)^2)

60 - 11i
--------------------- =
36 + 25

(60-11i) / 61

Hope that helped you!

~ ♥ ~

Answer 2

Whenever you have a problem like this you want to start by multiplying the the top and bottom by the complex conjugate of the denominator: (5-6i)/(6-5i)*(6+5i)/(6+5i)=(60-11i)/(61)

Answer 3

Multiply both top and bottom by the conjugate of the denominator, that is 6 + 5i; after collecting terms, you get the complex number:
(60 - 9i)/61.
You do this to eliminate the complex term in the denominator ie (6-5i)(6+5i)=36-25(i*i)=36+25=61.

Answer 4

5-6i/ 6-5i = 1
5-6i = 6-5i
5-6 = 6i-5i
-1 = 1i
i = -1/1
i = -1

GOOD LUCK¡¡¡¡¡¡¡¡

Answer 5

The answer would be
60-11i
----------
61