A skier slides horizontally along the snow for a distance of 27 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is µk = 0.060. Initially, how fast was the skier going?
2006-10-29 07:57:21 · 2 answers · asked by Alan l 1 in Science & Mathematics ➔ Physics
At the point that the skier stops to a halt, the work done by friction, W=umgd, is equal to the initial kinetic energy of the system, K=0.5mv^2. So 0= 0.5mv^2 - umgd. You may isolate v to arrive at the final answer.
u is the force of kinetic friction. Pardon if I do not know how to type in a "mu".
m is the skier's mass
g is the acceleration due to gravity
d is the distance traveled before the skier came to a halt
And by the way, you may cancell the term for the mass.
2006-10-29 08:08:48 · answer #1 · answered by pecier 3 · 0⤊ 0⤋
Do you have the mass of the skier? I think you will need that to solve the question, since kinetic friction increases with mass.
2006-10-29 08:04:03 · answer #2 · answered by John H 4 · 0⤊ 0⤋