A tenpin bowling lane is 17 m longer than it is wide. The area of the lane is 18 m^2. What are the dimensions?

Answer 1

Let width = w. Then length = w+17.

Area = length * width = (w+17)*w = 18.

w^2 + 17w = 18
w^2 + 17w - 18 = 0
(w+18)(w-1) = 0

So, w=1 or w=-18

Since width can't be negative, your answer is w=1

So the dimensions are width = 1m, length = 18m

~ ♥ ~

Answer 2

First, establish a relationship between the length and width.

Let x be the width of the lane. Then, the length must be x+17.

You know that area = length x width, so when you plug these in, you get:
18 = (x+17) * x

You can write this as a quadratic equation:
x^2 + 17x - 18 = 0

You can foil this into:
(x + 18)(x - 1) = 0

So, you know that x = 1 or -18. Well, you can't have a bowling lane that is -18 meters wide, so you are left with 1 meter wide. Thus, the length is 1 + 17 = 18 meters long.

And you can test this by looking at what you are given.
18 is indeed 17 longer than 1.
18 * 1 does give you 18 square meters.

Answer 3

Dimensions Of A Bowling Lane

Answer 4

Bowling Lane Width

Answer 5

If the area is 18 square metres and not 18 metres squared then let length be l and width be w.

l x w = 18
l - w = 17
l = 17 + w
so using substitution
(17 + w) x w = 18
17 + w = 18/w
17 = 18/w - w
The only number that fits is 1 so
17 + 18/1 - 1

L = 18
W =1

Answer 6

what's 18 x 1?

and what's 17 + 1?

Answer 7

it is 18 m long and 1 m wide

Answer 8

length x width = area
so
area/length = width

18/17 = 1.059m

length: 17m
width: 1.059m
area: 18m^2

there ya go! good luck!

oh sorry did wrong thing... well i gotta go good luck nyways!

Answer 9

why don't u get a calculator and figure it out urself. i ain't doing ur hw.