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Under what conditions will the arithmetic mean, (a+b)/2, of 2 nos. 'a' and 'b' equal to the nos. themselves?

How about the inequality involving the arithmetic and geometric mean of two nos. 'a' and 'b' assume the equality (a+b)/2 = square root of ab?

2006-10-29 06:11:16 · 3 answers · asked by bokuno_misa 1 in Science & Mathematics Mathematics

3 answers

whwn a=b

2006-10-29 06:17:16 · answer #1 · answered by raj 7 · 0 0

The arithmetic mean of 'a' and 'b' will be equal to the nos. themselves if a = b. For example the arithmetic mean of 3 and 3 is equal to (3+3)/2 = 3.

The same goes for the inequality involing the arithmetic and geometric means. The (a+b)/2 = square root of ab is true when a = b.

Here is your proof:
(a+b)/2 = square root of (ab) -> square both sides of the equation
(a+b)/2 * (a+b)/2 = (ab)
(a^2 + 2ab + b^2)/4 = ab
a^2 + 2ab + b^2 = 4ab
a^2 - 2ab + b^2 = 0
(a-b)^2 = 0
a - b = 0
a = b

2006-10-29 14:24:37 · answer #2 · answered by Ace 2 · 0 0

If and only if a = b.

2006-10-29 14:20:05 · answer #3 · answered by Helmut 7 · 0 0

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