2006-10-29 06:10:44 · 3 answers · asked by swt_gls 1 in Science & Mathematics ➔ Chemistry
That's a big if. How can 1 gram weight 28 g.
1 mole NH3 is 17 gr.
6.02x10^23 molecules ===> 1 mole ====> 17 grams
1 molecule ===> x grams
x = 17 / 6.02x10^23 = 2.8 x 10^(-23) gram
2006-10-29 06:17:29 · answer #1 · answered by Dr. J. 6 · 0⤊ 0⤋
You have got something wrong here to start with. Question probably gave a volume of NH3 gas, ie. One liter of NH3 weighed 28 grams at STP, standard temperature and pressure. Anyway, once you have that volume, divide that volume by the molar volume of gases which I believe is 22.4 liter per mole to find out what portion of a mole of NH3 you have. Multiply that by the weight given,28 gm. That should get you to the molar weight of NH3. Divide that by Avogadro's number, you will have to look it up to check, but I believe it is 6.03 x (10) to the -23 power. That should give you your answer. Ceck it is correct by finding the molar weight of NH3 from masses on Periodic chart. N is roughly 14 and H is one so molar weight is roughly 17.
2006-10-29 14:27:49 · answer #2 · answered by steveSang 2 · 0⤊ 0⤋
How can 1g weigh 28g?
2006-10-29 14:14:25 · answer #3 · answered by JJ 7 · 0⤊ 0⤋