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Question

On complete reaction with water, 0.10 grms of potassiun hydride KH yields a solution requiring 25.0cm^3 of 0.10M HCl for neutralisation.
The reaction occuring is :
KH + H20 --> KOH + H2
Calculate the RMM of potassium...

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Answer 1

25cc @ 0.1molar --> 0.0025 moles HCl.
1 mole HCl neutralises 1 mole KOH produced from 1 mole KH.
Therefore 0.10g KH is equivalent to 0.0025 moles KH, so the RMM of KH = 0.1/0.0025 = 40.
However, the RMM of H is 1, so that of K is 40-1 = 39.