Or will her bouyant force remain the same in greater depths?
Explain Please!
2006-10-29 03:58:45 · 5 answers · asked by Melissa 2 in Science & Mathematics ➔ Physics
It is greater. The deeper you go, the heavier the water becomes. The more the body tries to pull itself upward.
2006-10-29 04:00:25 · answer #1 · answered by IMHO 6 · 0⤊ 1⤋
As she swims deeper, the pressure from the water above her exerts pressure, which increases the density of the water she is currently in. This causes her to gain buoyant force. However, the same pressure which causes this will push down on her, counteracting the bouyant force. However, this counteraction is not a part of the buoyant force, so the buoyant force increases.
2006-10-29 12:01:40 · answer #2 · answered by (f-_-)f 2 · 0⤊ 1⤋
buoyant force depends on the weight of the volume of the water displaced by the swimmer. (Archimedes Law) So bouyant force will remain same. But he will feel lighter due to the pressure change of water
2006-10-29 12:00:45 · answer #3 · answered by The Potter Boy 3 · 0⤊ 0⤋
buoyant force decreases the lower the swimmer goes. this is not due to any changing property of the water. it is the swimmer that causes the change.
the lower she goes, the higher the water pressure is (naturally), and the greater her lungs are compressed. the torso becomes have smaller, in effect displacing less water.
archimedes principle suggests that buoyant force must decrease.
this does not happen in submarines because the hulls do not compress under high water pressure. the volume it displaces does not change no matter its depth in water.
2006-10-29 12:09:18 · answer #4 · answered by Anonymous · 1⤊ 0⤋
buoyant force depends only on the volume the body has displaced and density and g which are constant .so a swimmer does not lose or gain any buoyant foce provided the swimmer is completly submerged from the begining.
2006-10-29 12:10:59 · answer #5 · answered by Anonymous · 0⤊ 1⤋