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that is the integral of u^2/1+u^2 evaluated from 0 to x is equal to .5

2006-10-29 03:51:40 · 1 answers · asked by knh620 1 in Science & Mathematics Mathematics

1 answers

Int (u^2/(1+u^2)) = u - arctan(u) so
[x - arctan(x)] - [0 - arctan(0)] = .5
x - arctan(x) = .5
And if you can't take it from there, you is in *deep* trouble ☺


Doug

2006-10-29 04:10:05 · answer #1 · answered by doug_donaghue 7 · 1 0

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