in pythagoras theorem if the base of a triangle is 100m and one side is 50m what would be the length of the 3

Question

rd side be .this is my 13 year olds math homework and i got lost at school after fractions any help would be great

Answer 1

c^2 = 50^2 + 100^2 = 12500. so, c = sqrt(12500) = 111.803

Answer 2

Pythagoras theorem states
The square of the hypothenuse = sum of square of the base and the perpendicular side

Taking the data given by you, i.e. base=100 m and perpendicular side as 50 m then
square of hypothenuse = 100 squared + 50 squared = 10000 + 2500 = 12500
Hence hypothenuse = square root of 12500 = 111.8 m

Hence the answer is 111.8 m

Answer 3

Base = 100m
side/perpendicular =50m (not hypotenuse as its the biggest side)
apply the formula
b^2+p^2=h^2
100^2+50^2=h^2
h=(sqrt root)(12500)
h=111.8 m ans

Answer 4

You have to be careful here because the answer does depend where the right angle is in the triangle. The side opposite the right angle is the hypotenuse. Does your child have a drawing of the triangle. You have to check that one of the angles is a right angle or = to 90 degrees.

Answer 5

As Ratty says you have to be careful here.

If the 100m is the longest side then the answer is 100squared take away 50 squared

If it isn't the longest side the answer is 100squared plus 50squared.

Hope that helps.

Answer 6

If you are trying to work out the side opposite the right angle (the slopey side / the longest side) the answer is:
100 sqaured + 50 squared = 12500
then square root this answer = 111.8

If it's one of the shorter sides
100 sqaured - 50 sqaured = 7500
then square root this answer = 86.6

Hope this helps

Answer 7

225

Answer 8

Pythagorean Theorem

c² = a² + b²

c² = √(100)² + (50)²

c² = √10000 + 2500

c² = √12500

c = 111.8033989 m

c = 111.8 m Rounded to one decimal place

The answer is 111.8 m

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