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A 34.32 g stainless steel ball bearing at 117.82°C is placed in a constant-pressure calorimeter containing 120.0 mL of water at 18.44°C. If the specific heat of the ball bearing is 0.474 J/g°C, calculate the final temperature of the water. Assume the calorimeter to have negligible heat capacity.

2006-10-29 01:03:22 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

21.56 degrees

2006-10-29 01:58:27 · answer #1 · answered by JJ 7 · 0 0

1. Energy = (delta T)(mass)(specific heat)

2. For the ball you have the data for the right side, so solve for energy

3. Energy of the ball = energy of the water

4. Now for the water you have everything but the delta T of the water, solve for delta T and compute the final temp.

2006-10-29 10:09:58 · answer #2 · answered by Peter Boiter Woods 7 · 0 0

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