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I shall explain in setps
numerator = 16x^2y^2+24x^3y
take the GCD as common factor and factorise( 8 devides both so x^2 and y hence 8x^2y
8x^2y(2y+3x)
now denominaotor
= 8x^3y^2-4x^2y = 4x^2y(2xy-1)
devide to get 8x^2y(2y+3x)/(4x^2y(2xy-1)) = 2(2y+3x)/(2xy-1)

??? i dont understand how you got that. could i say 2x^y^2+3x^3y/xy^2??

2006-10-29 01:30:36 · 5 answers · asked by sweetypiexox 1 in Science & Mathematics Mathematics

the question was 16x^2y^2+24x^x^3y/8xy^2

2006-10-29 01:39:26 · update #1

5 answers

I think numerator is ok
denominator is ok
divsion step cancell common items and you are left with result

you cannot say you result
questionwas 16x^2y^2+24x3y/8x^3y^2-4x^2y
2nd question is different
16x^2y^2+24x^3y/8xy^2
take 8 x^2y common in numerator 8x^2y(2y+3x)
divde to get x(2y+3x)/y
you were right but additionally you can devide by xy as xy is common not both numerator and denominator so our result matches

2006-10-29 01:40:00 · answer #1 · answered by Mein Hoon Na 7 · 0 0

Hi sweetypie - let's try that again.

I think you have a typo in your last line, which may be throwing off some other potential answerers.

It looks like the original problem was to simply the expression

16x^2y^2 + 24x^3y
--------------------------
8x^3y^2 - 4x^2y

The first thing math_kp did was to take a common factor of 8x^2y out of both terms of the numerator. When you do that you can write the numerator as 8x^2y(2y + 3x)

The next thing he did was to take a common factor of 4x^2 y out of both terms of the denominator. When you do that you can write it as 4x^2y(2xy - 1)

Now let's put the numerator and denominator back together -
I will write them pictorially as:

8x^2y (2y + 3x)
--------------------
4x^2y (2xy - 1)

Now check both numerator and denominator for common factors which can be cancelled. The greatest common factor is 4x^2y, so we strike that out in both the numerator and the denominator leaving

2(2y+3x)
----------- as your final answer
(2xy - 1)

Hope that's clearer! You may find it easier to understand (both this and math_kp's answer) if you write them down on paper using the regular way of writing exponents with superscripts. (I had to do that to understand the question, and I've worked with math like this for 40 years!)

If you still need help keep asking, and be sure to provide a link to this question and the original one when you do - it will help your consultants get a better picture of the overall problem.

Good luck!

2006-10-29 01:56:07 · answer #2 · answered by Samienela 3 · 0 0

I think you are asking how to simplify the following:

(16x^2y^2 + 24x^3y)/(8x^3y^2 - 4x^2y)
If this is true, then:
[8x^2y(2y + 3x)]/[4x^2y(2xy - 1)]
=2(2y + 3x)/ (2xy - 1)

When you do the division, all you can do to simplify the expression is to replace 8x^2y/4x^y with 2.

This gives the proper answer.

Don't try to do more or less than is possible.

2006-10-29 01:00:30 · answer #3 · answered by ironduke8159 7 · 0 0

look at this:

8x^2y(2y+3x) / 4x^2y(2xy-1)

Remove for a second the following:

(2y+3x) / (2xy-1),

You have:

8x^2y / 4x^2y this equals 2.

So everything will equal:

2 *(2y+3x) / (2xy-1)

2006-10-29 01:44:24 · answer #4 · answered by Dr. J. 6 · 0 0

dude i have no clue ?? !!
Lol

2006-10-29 01:31:55 · answer #5 · answered by justmyself(: 1 · 0 1

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