I shall explain in setps
numerator = 16x^2y^2+24x^3y
take the GCD as common factor and factorise( 8 devides both so x^2 and y hence 8x^2y
8x^2y(2y+3x)
now denominaotor
= 8x^3y^2-4x^2y = 4x^2y(2xy-1)
devide to get 8x^2y(2y+3x)/(4x^2y(2xy-1)) = 2(2y+3x)/(2xy-1)
??? i dont understand how you got that. could i say 2x^y^2+3x^3y/xy^2??
2006-10-29
01:30:36
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5 answers
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asked by
sweetypiexox
1
in
Science & Mathematics
➔ Mathematics
the question was 16x^2y^2+24x^x^3y/8xy^2
2006-10-29
01:39:26 ·
update #1